[Cover] [Contents] [Index] Previous page Next Section

Page 285
help show 0285-001.gif, we use the s-m-n theorem (Theorem 2.1) to define two limiting-recursive functions g and h as follows. For each i and x define:
0285-002.gif
Since  l i.Ti is limiting recursive, it follows that one can construct a limiting-recursive g as above. For each 0285-003.gif, define
0285-004.gif
and, for each i > k, define
0285-005.gif
Since  l i.con(i, k), f, and g are limiting-recursive, it follows that one can construct a limiting-recursive h as above. (Note: One cannot, in general, limiting-recursively decide whether  Q k( j f(i)) is total. But this is not a difficulty since (13.1) affects only finitely many values of h.)
13.9 Claim
(a) For each i, if con(i, k), then  s g(i) is consistent with  Q k( j f(i)).
(b) For each 0285-006.gif, 0285-007.gif. Thus, 0285-008.gif.
(c) For each j > i, 0285-009.gif.
Proof: By Claim 13.6(C) for 0285-010.gif, we have that con(i, k) implies
0285-011.gif
Since 0285-012.gif, part (a) follows from the definition of g.
Part (b) follows from part (a) and definition of h.
For part (c), first note that, for 0285-013.gif, we have by (13.1) that  j h(i) is total, and hence, for such 0285-014.gif, part (c) clearly holds. So assume i > k and suppose  j h(i) ~  j h(j). By

 
[Cover] [Contents] [Index] Previous page Next Section