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For each and t > 1, let and, for each define . So (, , ) is just the uniform probability space on . Easy exercise: Show that, for each k and t, and satisfy the conditions for a Borel field and probability measure, respectively. |
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Now let us consider the problem of constructing for an appropriate probability space (, , ) where, as usual, t is an integer greater that 1. Somehow, this space should be the "limit" of the (, , )'s. Moreover, we want the probability that an infinite sequence of coin flips starts with a 0 (respectively, 1, . . ., t - 1) to be 1/t, and, in general, we want the probability that an infinite sequence of coin flips has r (a particular finite t-ary sequence) as an initial subsequence to be . So, defining, for each , |
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we know that all of the should be in with . Thus, we take to be the Borel field generated by , and, less obviously, for each , define |
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It can be shown (see Dudley [56]) that this is a probability measure for . This probability space on will suffice for our purposes. Henceforth, we will say that an is measurable if and only if . Many natural sets turn out to be measurable, as shown by the next lemma. First, we introduce a bit of terminology. For and , we say a relation is arithmetic if and only if P can be expressed in the language of first-order arithmetic augmented by a 1-ary function variable O. So for example, the relation "there are infinitely many n such that O(n) = 0" is expressible by: . (Rogers discusses and characterizes such arithmetic relations in Section 15.2 of [158].) |
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9.11 Lemma Suppose , , and is arithmetic. Then, for each x1, . . ., xk, the set is measurable. |
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Proof: Without loss of generality, suppose that for all O, x1, . . . xk, |
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