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This conjecture is appealing but false. The collection of self-describing functions, , is identifiable, but it is easily shown that cannot be identified by any scientist that is an enumerator. |
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In defense of Gold's intuitions, refutation of his conjecture via seems like a trick. After all, to identify requires no more than fetching some coded value from the input function. In the 1970's, Barzdins
* formulated a more sophisticated version of Gold's conjecture designed to transcend such counterexamples. He reasoned that if a class of functions is identifiable only by way of a self-referential property, then there would be a total recursive operator that would transform the class into an unidentifiable one. The idea is that if a scientist is able to find the embedded self-referential information in the elements of a class, so can a total recursive operator which can then weed out this information. To see this in the context of , consider the operator such that, if , then g(x) = f(x + 1), for all . essentially "shifts the function f to the left." It is easy to see that , and we know from prior work that . Thus, transforms the identifiable class into an unidentifiable class by removing the self-referential information from that made it identifiable. |
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Informally stated, Barzdins'* conjecture is: |
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If the projection of a class of functions under all total recursive operators is identifiable, then the class is identifiable by enumeration. |
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13.3 Definition (Fulk [72]) is said to be robustly Ex-identifiable just in case for all total recursive operators , . |
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13.4 Conjecture (Barzdins* as formalized by Fulk [72]) Every subclass of that is robustly Ex-identifiable is contained in some r.e. indexable subclass of . |
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This conjecture is also appealing, and also false. The next section presents a cunning refutation due to Fulk [72]. Beyond simply showing the conjecture to be false, the refutation demonstrates an identification strategy that is strictly more general than enumeration but in the same spirit. |
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§13.2 Fulk's Refutation of Barzdins'* Conjecture |
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