|
|
|
|
|
(b) , and |
|
|
|
|
|
|
|
|
(c) for all with and , we have that . |
|
|
|
|
|
|
|
|
We refer to s as an OATxtEx-locking sequence for M on L. |
|
|
|
|
|
|
|
|
Proof (of Proposition 11.15): Define |
|
|
|
|
|
|
|
|
, and |
|
|
|
|
|
|
|
|
. |
|
|
|
|
|
|
|
|
11.17 Claim . |
|
|
|
|
|
|
|
|
Proof: We first note that by the s-m-n theorem (Theorem 2.1) there are recursive functions g0 and g1 such that for all i and j: |
|
|
|
|
|
|
|
|
Consider the following oracle scientist (with oracle X). |
|
|
|
|
|
|
|
|
Program for MX on s
If for some and some nonempty ,
then output 0 and halt.
Otherwise:
Let i and D be such that ![0258-014.gif](0258-014.GIF)
If ![0258-015.gif](0258-015.GIF)
![](tab.gif) then output g0(i)
![](tab.gif) else output g1(i, j), where j is the canonical index of D. |
|
|
|
|
|
|
|
|
We leave it as an exercise to show that MB TxtEx-identifies . |
|
|
|
|
|
|
|
|
11.18 Claim . |
|
|
|
|
|
|
|
|
Proof: Suppose by way of contradiction that there is an M that OCTxtEx-identifies. We show that ![0258-017.gif](0258-017.GIF) |
|
|
|
|
|
|
|
|
Suppose i is such that Ai is finite. Then by our definition of , Thus, by Lemma 11.16 there is an OCTxtEx-locking sequence for M on . |
|
|
|
|